2x-45=8x^2+2x

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Solution for 2x-45=8x^2+2x equation: 



2x-45=8x^2+2x

We move all terms to the left:

2x-45-(8x^2+2x)=0

We get rid of parentheses

-8x^2+2x-2x-45=0

We add all the numbers together, and all the variables

-8x^2-45=0

a = -8; b = 0; c = -45;
Δ = b2-4ac
Δ = 02-4·(-8)·(-45)
Δ = -1440
Delta is less than zero, so there is no solution for the equation

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